Interpret:How do I declare the Swift closure?

Today, a friend recommended an interesting page,A domain name is like:

http://fuckingclosuresyntax.com

In the Swift,All functions are closures,Standard functions are just the most complete closures name with parameters。

All right.,The following is the text


 

 

Asvariable:


 

AsOptional variable:

 

AsType alias:

 

Asconstant:

 

AsWhen the function call parameters:

 

AsFunction parameters:

 

AsAnd using the parameters of the function type inference:

 

AsEstimation function parameters and return type:

 

AsThe last parameter of the function:

 

As the last parameter to the functionParameter names and abbreviations:

 

And as a function of the last parameterAnd concluded that the return value:

 

As the last parameter to the function,A presence function as a reference:

 

As a function parameterWith default capture:

 

As a function parameterWith default parameters to infer the type of capture and return type and:

 

This site does not list ready to use all closures。
By Zev Eisenberg, Yes, that's right Mike Walker Sorry, The latter is unlikely to have a good impression on these things。

Original article written by LogStudio:R0uter's Blog » Interpret:How do I declare the Swift closure?

Reproduced Please keep the source and description link:https://www.logcg.com/archives/1055.html

About the Author

R0uter

The non-declaration,I have written articles are original,Reproduced, please indicate the link on this page and my name。

Leave a Reply

Your email address will not be published. Required fields are marked *